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Tomcat7开启SSI功能 1.官方参考文档地址: http://httpd.apache.org/docs/current/howto/ssi.html#basicssidirectives https://tomcat.apache.org/tomcat-7.0-doc/ssi-howto.html 2.配置步骤 (1)修改tomcat根目录下的conf文件夹中的context.xml,修改如下: ~~~xml <Context privileged="true"> <!-- Default set of monitored resources --> <WatchedResource>WEB-INF/web.xml</WatchedResource> </Context> ~~~ 即在Context 中增加privileged="true" (2)修改tomcat根目录下的conf文件夹中的web.xml,将SSI的Servlet的配置取消注释,并增加编码配置,否则可能出现乱码 ~~~xml <servlet> <servlet-name>ssi</servlet-name> <servlet-class> org.apache.catalina.ssi.SSIServlet </servlet-class> <init-param> <param-name>buffered</param-name> <param-value>1</param-value> </init-param> <init-param> <param-name>inputEncoding</param-name> <param-value>UTF-8</param-value> </init-param> <init-param> <param-name>outputEncoding</param-name> <param-value>UTF-8</param-value> </init-param> <init-param> <param-name>debug</param-name> <param-value>0</param-value> </init-param> <init-param> <param-name>expires</param-name> <param-value>666</param-value> </init-param> <init-param> <param-name>isVirtualWebappRelative</param-name> <param-value>false</param-value> </init-param> <load-on-startup>4</load-on-startup> </servlet> ~~~ 取消SSI Servlet的mapping注释,增加*.html,因为我们是在html中引入shtml的,如果不配置*.html,则tomcat不会处理html中的ssi指令 ~~~xml <servlet-mapping> <servlet-name>ssi</servlet-name> <url-pattern>*.shtml</url-pattern> <url-pattern>*.html</url-pattern> </servlet-mapping> ~~~